99 10

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What is the maximum possible work function of the cathode in eV?

You need to design a photodetector that can respond to the entire range of visible light.What is the maximum possible work function of the cathode in eV?

My wrong calculations: Please help!
I used Wf=hf-KE
KE=0
Wf= (1.99*10^-25)/400*10^-9 - 0 =
Wf=4.975*10^-19-->3.11eV

Visible wavelength range 390nm (blue) to 750 nm (red)

You have used a photon of the highest energy in the visible spectrum when you should have used one with the lowest energy. The lowest energy will have the longest wavelength; in other words the red end at 750nm. If the photoelectric device responds at the lower energy then it will respond at the higher energy also.

I used Wf=hf-KE
KE=0
Wf= (1.99*10^-25)/750*10^-9 - 0 =
Wf=2.65*10^-19-->1.65eV

I think the confusion has crept in by the use of the word maximum. Clearly 3.11 eV is greater than 1.65 eV but using 3.11eV will respond only to the short wavelength (blue) end and any wavelengths shorter than this but not to the other part of the visible towards the red end were the wavelengths are longer and the energy of the photon less.

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